Soal
1. 2ABF316
+ 5AFC16 - 3FFA16 = 2C6F516
2. 73158
– 126138 + 10018 = -22758
3. 10012
+ 110112 – 101012 = 11112
JAWAB
:
1.
2ABF316
5AFC16
+
306EF16
3FFA16
-
-
2C6F516
2.
126138
73158
-
-
-32768
10018
+
+
-22758
3.
10012
110112
+
1001002
101012
-
11112
11112
Coba anda kerjakan dengan mengkonversikan terlebih dahulu ke
desimal kemudian hasilnya konversikan kembali ke bilangan yang diinginkan !!!
1. 10102
+ A5B42 = 1226762
2. 7158
- 100012 = 1111216
3. (
F116 X 10012 )
+ ( 3128 : 102 ) = 100100000100 2
JAWAB :
1.
0 X
20 = 0
1 X 21 = 2
0 X 22 = 0
1 X 23 = 8
+
+
( 102 )
4 x 160 = 4
B X 161 =
176
5 X 162 = 1280
A x 16 3 =
40960
+
( 4242016 )
( 4242016 )
102 + 4242016 = 42430
Diubah ke oktal
42430 : 8 = 5303 sisa 6
5303 : 8 = 662 sisa 7
662 : 8 = 82 sisa 6
82 : 8 = 10 sisa 2
10 : 8 = 1 sisa 2
1 : 8
= 0 sisa 1
( 1226768 )
2.
5 x 80 = 5
1 x 81 = 8
7 x 82 = 448
( 4618 )
1 x 20 = 1
0 x 21 = 0
0 x 22 = 0
0 x 23 = 0
1 x 24 = 16
(172 )
4618 - 172
= 444
Diubah ke heksadesimal
444 : 16 = 27 sisa 12
27 : 16 = 1 sisa 11
1 : 16 = 0 sisa 1
( 1111216 )
3. 1 x 160 = 1
F x 161 = 240
1 x 20 = 1
0 x 21 = 0
0 x 22 = 0
1 x 23 = 8
241 x 9 =2169
3 x 80 = 3
1 x 81 = 8
2 x 82 = 128
1 x 20 = 1
0 x 21 = 0
139 : 1 = 139
Jadi 2169 + 139 =2308
Diubah ke biner
2308 : 2 = 1154 sisa 0
1154 : 2 = 577 sisa 0
577 : 2 = 288 sisa 1
288 : 2 = 144 sisa 0
144 : 2 = 72 sisa 0
72 : 2 = 36 sisa 0
36 : 2 = 18 sisa 0
18 : 2= 9 sisa 0
9 : 2 = 4 sisa 1
4 : 2 = 2 sisa 0
2 : 2 = 1 sisa 0
1 : 2 = 0 sisa 1
(1001000001002 )
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